Urea Application in Sorghum Field @ Champaign, Illinois (25 June 2024)
■ Unit conversion
□ Area
| Acre | ha | m2 | ft2 | |
| Acre | 1 | 0.404686 | 4,046.86 | 43,560 |
| ha | 2.47105 | 1 | 10,000 | 107,639 |
| m2 | 0.000247105 | 0.0001 | 1 | 10.7639 |
| ft2 | 0.000022956 | 0.00000929 | 0.092903 | 1 |
□ Weight
| lbs | kg | |
| lbs | 1 | 0.453592 |
| kg | 2.20462 | 1 |
| bushel [corn] | 56 | 56 * 0.453592 = 25.4 |
| bushel [wheat] | 60 | 60 * 0.453592 = 27.2 |
| bushel [soybean] | 60 | 60 * 0.453592 = 27.2 |
My target nitrogen application rate is 100 N lbs / acre in sorghum, and my plot size is 250 ft2
1 acre = 43,560 ft2
→ 100 lbs / 43,560 ft2
100 lbs : 43,560 ft2 = x lbs : 250 ft2
∴ x = (250 * 100) / 43560
→ 0.574 lbs
1 lbs : 0.453592 kg = 0.574 lbs : x kg
∴ x = 0.260 kg
Based on the target rate of 100 N lbs/acre, the amount of nitrogen for my plot size is 0.260 g. I’ll apply nitrogen as urea, which contains 46% nitrogen. Here is the equation to calculate the amount of urea.
Therefore, I need to apply ca. 565 g of urea to meet my nitrogen requirement of 260 g for your plot size.
